1100=16x^2

Solution for 1100=16x^2 equation:

1100=16x^2

We move all terms to the left:

1100-(16x^2)=0

a = -16; b = 0; c = +1100;
Δ = b2-4ac
Δ = 02-4·(-16)·1100
Δ = 70400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{70400}=\sqrt{6400*11}=\sqrt{6400}*\sqrt{11}=80\sqrt{11}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80\sqrt{11}}{2*-16}=\frac{0-80\sqrt{11}}{-32}
=-\frac{80\sqrt{11}}{-32}
=-\frac{5\sqrt{11}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80\sqrt{11}}{2*-16}=\frac{0+80\sqrt{11}}{-32}
=\frac{80\sqrt{11}}{-32}
=\frac{5\sqrt{11}}{-2}
$